4 If the second derivative f '' is negative () , then the function f is concave down ( ) 5 The point x = a determines a relative maximum for function f if f is continuous at x = a , and the first derivative f ' is positive () for x < a and negative () for x > a The point x = a determines an absolute maximum for function f if itIf y = xsqrt(1 x^2) then y^2 = x^2(1 x^2) = x^2 x^4 Now differentiate implicitly 2ydy = (2x 4x^3)dx, therefore, cancel 2s and x and make dy/dx the subject of the formula ydy = (x 2x^3)dx = x(1 2x^2)dx => dy/dx = x(1 2x^2)/y => dy/Jonbenedick shared this question 7 years ago Answered How can you graph the derivative of y=x!?
Derivative Wikipedia
